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(F)=1.5-12F-6F^2
We move all terms to the left:
(F)-(1.5-12F-6F^2)=0
We get rid of parentheses
6F^2+12F+F-1.5=0
We add all the numbers together, and all the variables
6F^2+13F-1.5=0
a = 6; b = 13; c = -1.5;
Δ = b2-4ac
Δ = 132-4·6·(-1.5)
Δ = 205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{205}}{2*6}=\frac{-13-\sqrt{205}}{12} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{205}}{2*6}=\frac{-13+\sqrt{205}}{12} $
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